4y^2=120

Solution for 4y^2=120 equation:

4y^2=120

We move all terms to the left:

4y^2-(120)=0

a = 4; b = 0; c = -120;
Δ = b2-4ac
Δ = 02-4·4·(-120)
Δ = 1920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1920}=\sqrt{64*30}=\sqrt{64}*\sqrt{30}=8\sqrt{30}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{30}}{2*4}=\frac{0-8\sqrt{30}}{8}
=-\frac{8\sqrt{30}}{8}
=-\sqrt{30}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{30}}{2*4}=\frac{0+8\sqrt{30}}{8}
=\frac{8\sqrt{30}}{8}
=\sqrt{30}
$